#如果 a+b+c=1000, 且 a^2 + b^2 = c^2 (a,b,c 为自然数), 如何求出所有a,b,c 可能的组合
import time
start_time = time. time()
for a in range (0,1001):
    for b in range (0,1001):
        for c in range (0,1001):
            if a+b+c==1000 and a**2+b**2==c**2:
                print("a:",a,"b:",b,"c",c)

#执行次数 f(n)=n*n*n*2

#获取时间
end_time = time. time()
print("所花费的时间:",(end_time - start_time))
